Due Date: Thursday, July 5.
Objective: The goal of this assignment is to practice
Background. In 2008, three UTEP students participated in
the Olympic Games. Let us help a UTEP athlete train for the
future Olympics. Specifically, he trains for a 100 meter race.
The world record is w = 9.58 sec. After each training session,
the difference r − w between the athlete's running time r
and the world record w decreases by a constant factor f
(depending on the athlete). To be more precise, the running
times r(t+1) and r(t) after two consequent training sessions
are related by the formula r(t + 1) − w = f * (r(t)
− w), which is equivalent to r(t + 1) = w + f *
(r(t) − w). From this equation, we can
determine the parameter f if we know the running times r(0) and
r(1) before and after the first training session, as f
= (r(1) − w) / (r(0) − w). Once the value
f is determined, we now need to compute, for a given integer T,
the expected running time r(T) after the T-th training session.
Assignment. Write two methods that, given:
athlete's running time r(T) after all T training sessions:
running time r(0) before the first training session,
running time r(1) after the first training session, and
the total number T of training sessions,
In both methods, we should
first compute the factor f as f = (r(1) − w) /
(r(0) − w), and then the values r(t) by using
the relation r(t + 1) = w + f * (r(t) −
w). (The ideas behind both methods are explained in
similar examples in the class and in the book.)
- a method based on recursion and
- an iterative method
that uses a simple for loop.
Once the methods are up and running, compare the speed of these
two approaches by using the same techniques as in Assignment 3.
Record your observations and be able to explain what is
happening to your TA when you demo your program.
Testing. Do not forget to test your method. To test your
method, pick any value of r(1) and f. For example, if you take
r(0) = 10.0 and f = 0.5, then you should get r(0)
− w = 10.0 − 9.58 = 0.42, so r(1)
= w + 0.5
* (r(0) − w) = 9.58 + 0.5 * 0.42 = 9.58 + 0.21 =
9.79, and similarly, r(2) = w + 0.5 * (r(1)
− w) = 9.58 + 0.5 * 0.21 = 9.58 + 0.105 = 9.685,
and r(3) = w + 0.5
* (r(2) − w) = 9.58 + 0.5 * 0.105 = 9.58 + 0.0525 =
9.6325, etc. This means that your program, when you
pass it the values r(0) = 10.0, r(1) = 9.79, and T = 3, should
return 9.6325 as the value for r(T). Specifically, your program
should first find the factor f by applying the above formula,
then compute r(2) and r(3). Feel free to test your method on
other similar examples as well: the more you test, the more
confident you will be that your program is correct.